(5x+4)(2x^2-17x-9)=0

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Solution for (5x+4)(2x^2-17x-9)=0 equation: 


Simplifying
(5x + 4)(2x2 + -17x + -9) = 0

Reorder the terms:
(4 + 5x)(2x2 + -17x + -9) = 0

Reorder the terms:
(4 + 5x)(-9 + -17x + 2x2) = 0

Multiply (4 + 5x) * (-9 + -17x + 2x2)
(4(-9 + -17x + 2x2) + 5x * (-9 + -17x + 2x2)) = 0
((-9 * 4 + -17x * 4 + 2x2 * 4) + 5x * (-9 + -17x + 2x2)) = 0
((-36 + -68x + 8x2) + 5x * (-9 + -17x + 2x2)) = 0
(-36 + -68x + 8x2 + (-9 * 5x + -17x * 5x + 2x2 * 5x)) = 0
(-36 + -68x + 8x2 + (-45x + -85x2 + 10x3)) = 0

Reorder the terms:
(-36 + -68x + -45x + 8x2 + -85x2 + 10x3) = 0

Combine like terms: -68x + -45x = -113x
(-36 + -113x + 8x2 + -85x2 + 10x3) = 0

Combine like terms: 8x2 + -85x2 = -77x2
(-36 + -113x + -77x2 + 10x3) = 0

Solving
-36 + -113x + -77x2 + 10x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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